0.25t^2=10t

Solution for 0.25t^2=10t equation:

0.25t^2=10t

We move all terms to the left:

0.25t^2-(10t)=0

a = 0.25; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·0.25·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*0.25}=\frac{0}{0.5}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*0.25}=\frac{20}{0.5}
=40
$